# Simple Rays

Simple ray tracer written in Rust

## Simple ray tracer written in Rust from scratch

I've just finished my first semester at the Faculty of Applied Mathematics and Computer Science at the Belarusian SU. I missed conventional programming a bit and I'm curious to see how I can apply any of my new knowledge. Finding exciting yet widely applied and simple topic for a side project turned out to be not that simple. Linear algebra is broadly used in computer graphics, where I previously came across matrices, transformations and projections when working with OpenGL, but back then I had only a somewhat shallow understanding of those topics. I've never done any ray tracing, so my choice simply fell on it. Besides that it somewhat overhyped now and has very little to almost no theory - just vectors and geometry. I haven't read any posts or books specifically on ray tracing, so my approach surely won't be the fastest or most optimal, but I think it will be quite interesting to come up with a working one.

I've chosen Rust ? because it's my favourite programming language and I haven't used it for a while. So let's start!

### Everything starts with a ray

I've defined some utils for working with floating point numbers, a Point and Vector struct and some ugly convenient macros for creating vectors and points. I first used `f32` for all calculations, but then found out that precision degrades very quickly, especially for extremely sharp angles. At that point I had already marked the Point struct as `Copy`, so I kept the marker, even though its new size of 24 bytes exceeded twice the machine word. This is just a general rule of thumb and I bet it has almost no effect in this case, as the average number of arguments in generally low.

Raytracing has obviously something to do with casting rays. A ray is just a line with a positive direction. A line in space can be defined by a point and a direction vector. What matters is that we can describe every point on this line with a single number.

``````impl Line {
pub fn at(&self, t: f64) -> Point {
self.origin + t * self.direction
}
}
``````

To create an image we have to find out how to intersect rays with objects in space. Many might associate ray tracing with spheres, because they nicely demonstrate many visual effects. But I won't cover any of those effects. So we'll focus just on triangles. Besides that triangles can be used to approximate almost any shape and 3d models consists of them. But how do we find the intersection of a line and a triangle?

### The plane

First, we have to define the plane which contains the triangle. A plane can be defined by a single point and a normal vector. The normal vector is actually the cross product of any two vectors in the plane. So lets implement the cross product for vectors:

``````impl Vector {
pub fn cross(&self, v2: Vector) -> Vector {
Vector {
x: (self.y * v2.z - self.z * v2.y),
y: -(self.x * v2.z - self.z * v2.x),
z: (self.x * v2.y - self.y * v2.x),
}
}
}
``````

Then we can turn our point-normal pair into a well known equation `Ax + By + Cz + D = 0`, so our Plane constructor looks like:

``````impl Plane {
pub fn new(p: Point, v1: Vector, v2: Vector) -> MathResult<Self> {
match v1.cross(v2) {
v if v.is_zero() => Err(MathError::CollinearVectors),
Vector { x, y, z } => Ok(Plane {
a: x,
b: y,
c: z,
d: -(x * p.x + y * p.y + z * p.z),
})
}
}
}
``````

To find the intersection of a line and a plane, we can express the coordinates of all points on the line in terms of our "line parameter", and then substitute those relations into the planes equation. By solving the equation for the "line parameter" we get the point of intersection.

### Does the triangle contain it?

There are many ways to determine whether a triangle contains a point in two dimensions, so I first thought of equivalent approaches: introducing a two dimensional coordinate system on the plane or looking for intersections with the triangles sides.

One approach is based on the fact, that if a point lies inside a triangle, then it lies in the same half plane for each side of the triangle (right or left half plane, depends on the order of traversal). We can generalize this property for the third dimension be reviewing one other property for vectors on the plane: the cross product of a vector with all vectors pointing right of it will point upwards, and for all vectors left of it - downwards (or downwards/upwards if the order of vectors in the cross product is flipped). So if a point lies inside a triangle, then all cross products of each side with the corresponding vector, connecting the vertex and the point of intersection, point in the same direction:  That results in a simple implementation using the cross product that we already defined:

``````impl Triangle {
fn is_inside(&self, pt: Point) -> bool {
self.vertices.iter().enumerate()
// calculate the cross products for each vertex
.map(|(pos, vertex)| -> Vector {
let next_vertex = self.vertices[(pos + 1) % 3];
vector!(cross   vector!(vertex, pt),
vector!(vertex, next_vertex))
})
// check if each vector is codirectional with the sum of the previous ones
// that is equivalent to all of them being pairwise codirectional
.fold(Some(vector!()), |last_opt, v| -> Option<Vector> {
match last_opt {
Some(last) => if v.is_codirectional(last) { Some(v + last) } else { None }
None => None,
}
}).is_some()
}
}
``````

A ray intersects a triangle only if it intersects the plane containing the triangle and the point of intersection lies inside the triangle. Now we know how to verify both conditions, so lets move on to casting rays.

### How to cast rays?

To create an image, we have to cast rays from an "eye" (or camera, or origin) through an imaginary grid. Finding the best approach to generate such a grid turned out to be an interesting task. For the sake of simplicity we'll say that our eye always looks at the origin and its rotation is locked. If it were to be an airplane, we'd say that its roll is always zero :) Lets also say, that the global Y axis is the one that points "up". That means, that if the angle between the eye and the Oxz plane is not 90 degrees (a top-down projection), then "up" on the image always points "up" in the 3d world. Now we can see that the plane formed by the "eye" ray and the Y axis will always be perpendicular to the Oxz plane.

Given those relations, there is a simple way to define the imaginary grid plane with a 2d coordinate system fixed at the global origin:

• Because our rotation is always zero, our grid will be perpendicular to the "eye"-Y axis plane, so we can define our local X axis (Vx on the image) as the cross product of the Y axis and the "eye" ray.
• Our local Y axis (Vy on the image) can be defined as the cross product between the "eye" ray and the local X axis. Because I want the axes to point how I'm used to, we I have to "flip" x and y when converting image coordinates into rays:

``````fn create_ray(env: &Environment, (x, y): (u32, u32)) -> Line {
let interpolated = |cur: u32, max: u32| -> f64 {
2f64 * (cur as f64 / max as f64) - 1f64
};
let vx = vector!(cross env.origin, vector!(axis y)).normalized();
let vy = vector!(cross env.origin, vx).normalized();
let pt = vector!()
+ interpolated(y, IMAGE_SIZE.1) * env.grid_size * vx
+ interpolated(x, IMAGE_SIZE.0) * env.grid_size * vy;
Line {
direction: vector!(env.origin, pt),
origin: env.origin,
}
}
``````

### Turn the lights on!

We already know how to find intersections of lines and triangles. But what about the brightness? In our world all objects will be opaque and there will be only one source of light - the sun. To find out whether a point on a triangle is lit by the sun, we have to cast another ray. If the ray from the intersection point to the sun intersects any other triangle, then our pixel is covered by a shadow. Because we don't consider on which side the "eye" ray intersected the plane, we have to make sure that both the sun and the "eye" are in the same half-space, bounded by the surface plane. Without this check both sides of each triangle would have the exact same lighting, which is obviously not true for non-transparent shapes. Two points are in the same half-space if their corresponding values for the plane formula are of the same sign.

As far as I know, real raytracing casts many more rays to compute reflections, refractions, scattering etc. Instead, I decided to implement something similar to the Phong shading model, which I'm familiar with from OpenGL. In this model, the brightness of a "pixel" consists of its ambient, diffuse and specular components:

• Every pixel is at least as bright as the ambient brightness, even if it lies in a shadow
• A pixel is brighter if it directly faces the sun, and darker if the angle between the surface normal and the sun ray is greater. How much this brightness varies in relation to the angle is the defined by the diffuse part.
• Specular lighting indicates how rough or even a material is (the small bright spot on spheres), but it won't be used here

Instead of finding the angle between the surface normal and the "sun" ray, we'll find just the cosine. The closer the absolute value is to 1, the closer the normal is to being aligned with the "sun" ray. We can find the cosine using the dot product.

In our case we will use the ambient color only for covered pixels.

``````fn compute_lights(env: &Environment, surface: &Triangle, pt: Point) -> f32 {
let sun_ray = Line {
direction: vector!(pt, env.sun),
origin: pt,
};
let covered = env.surfaces.iter()
.filter(|sf| !sf.triangle.contains(pt))
.map(|sf| sf.triangle.intersect(&sun_ray))
// check if any intersection lies on the positive direction of the ray
.any(|opt| opt.map(|t| t >= -FLOAT_EPS).unwrap_or(false));
let different_halves = surface.plane.subs(env.origin)
* surface.plane.subs(env.sun) <= 0.0;
if covered || different_halves {
env.ambient_light
} else {
let normal = surface.plane.normal();
let cos = sun_ray.direction.cos(normal).abs() as f32;
(1.0 - env.diffuse_light) + cos * env.diffuse_light
}
}
``````

### Lets cast finally

It's pretty clear that from all the intersections, we have to discard those, which are behind our "eye", and choose the closest one from the remaining. Then we compute the brightness at the point of intersection and multiply it by the surface color:

``````fn cast_ray(env: &Environment, ray: &Line) -> [u8; 3] {
let intersection_opt = env.surfaces.iter()
.map(|sf: &ColoredSurface| sf.triangle.intersect(ray).map(|t| (t, sf)))
.filter(Option::is_some).map(Option::unwrap)
// check if it lies on the positive direction of the ray
.filter(|is| is.0 >= -FLOAT_EPS)
// find closest to the origin
.min_by(|a, b| a.0.partial_cmp(&b.0).unwrap());
if let Some((ray_param, surface)) = intersection_opt {
let brightness = compute_lights(&env, &surface.triangle, ray.at(ray_param));
surface.color.iter()
.map(|c| (*c as f32 * brightness) as u8).try_collect().unwrap()
} else {
VOID_COLOR
}
}
``````

### Last steps

Now we know how to cast rays, but how do we generate an image? The easiest way is just to save the ray casting results in an byte array (RBG, 3 bytes per pixel) and then convert it into a png. We'd also like to import 3d models to build more complex shapes. Oh, and using Rust and not going multi-threaded would be kind of lame.

I'm using:

• The image crate to write the color array to a png file.
• obj-rs to parse wavefront obj files and turn them into triangles.
• scoped_threadpool to avoid cluttering the code with `Arc`s when they're unnecessary
• And of course the good old num_cpus

### Results:

The results might seem not that impressive visually, but we're actually rendering 3d models (with shadows!) in less than just 400 lines of pure Rust without any graphics or maths libraries.

Low poly wavefront from Kenney: Moving sun: By using sine in the interpolation function in `create_ray`, we can create some space curvature :) My first three triangles (and an odd rotation bug): Open Source Agenda is not affiliated with "Simple Rays" Project. README Source: dranikpg/simple-rays
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